This is the third and (hopefully) final post about finding all simple cycles in an undirected graph. In the first post, I discussed the problem briefly and described a simple, efficient iterative algorithm. In the second post, I posed (but definitely did not recommend) a mixed integer linear program (MILP) to find all simple cycles. Here I will discuss an alternative MILP approach, specific to CPLEX. To make sense of it, you will definitely need to have read the second post. Java code demonstrating all three methods is available from my repository.
Recent versions of CPLEX have a feature called the solution pool, about which I have previous written. One use is to accumulate solutions (including suboptimal ones if desired) encountered along the way to the optimal solution of a MILP model. Another, using the IloCplex.populate() method in the Java API, is to just generate a gaggle of feasible solutions. So the approach I propose here is to build a MILP model for finding a single simple cycle, set the solution pool population limit parameter (the maximum number of solutions to retain) to something really large and the solution pool intensity parameter (how hard CPLEX works to churn out solutions) to its maximum value, and then use the populate() method to find simple cycles. This is implemented in the SingleCycleMIP.java class in my code.
Actually, I'm not sure setting the intensity parameter is necessary. On the small test graph, results were similar no matter what intensity setting I used. CPLEX stopped with 160 solutions, many of which were duplicates. After removing duplicates, there were 13 distinct simple cycles, which matches what the other methods found. The only difference was run time, which was a fraction of a second using either the default intensity or the maximum intensity (4) and about two seconds using the minimum intensity (1). Either way, it was much faster than the full MILP model, at least on this small test graph.
The MILP model used here is a subset of the model in the previous post. The model has no objective value (or equivalently minimizes the constant zero function). We drop the $u$ variables (which were used to ensure that cycles were distinct) and the $x$ variables (which signaled whether a slot in the solution was filled with a cycle or not). For all other variables, we drop the $c$ subscript (which slot is being filled), since we are only building one cycle. The "one anchor per cycle" constraint becomes $\sum_i w_i = 1,$ and other constraints involving $u$ and/or $x$ are dropped.
One issue with this model is that the same cycle can be discovered multiple times, either because its orientation is reversed (so the "clockwise" and "counterclockwise" versions are considered distinct) or possibly because minor difference (rounding error) in the flow variables make two copies of the same solution look distinct. Regardless of the reason, the fact CPLEX terminated with 160 solutions when only 13 cycles exist tells you duplication is happening. Fortunately, we do not have to monkey with the model (or set overly finicky values for tolerance values); we can just filter the pool after the run and weed out the duplicates (which my code does). The alternative would be to use a callback (either an incumbent callback if you are using legacy callbacks, or the more current generic callback in "candidate" context) to weed out duplicates as they arise. Since the logic to be used in the callback is the same as the logic used in post-processing, I cannot see any virtue to using a callback, and it definitely would complicate the code.
With that I am hopefully done with this topic. :-)
No comments:
Post a Comment
Due to intermittent spamming, comments are being moderated. If this is your first time commenting on the blog, please read the Ground Rules for Comments. In particular, if you want to ask an operations research-related question not relevant to this post, consider asking it on Operations Research Stack Exchange.